2x^2+20x=192

Solution for 2x^2+20x=192 equation:

Simplifying
2x2 + 20x = 192

Reorder the terms:
20x + 2x2 = 192

Solving
20x + 2x2 = 192

Solving for variable 'x'.

Reorder the terms:
-192 + 20x + 2x2 = 192 + -192

Combine like terms: 192 + -192 = 0
-192 + 20x + 2x2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-96 + 10x + x2) = 0

Factor a trinomial.
2((-16 + -1x)(6 + -1x)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(-16 + -1x)' equal to zero and attempt to solve:

Simplifying
-16 + -1x = 0

Solving
-16 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + -1x = 0 + 16

Combine like terms: -16 + 16 = 0
0 + -1x = 0 + 16
-1x = 0 + 16

Combine like terms: 0 + 16 = 16
-1x = 16

Divide each side by '-1'.
x = -16

Simplifying
x = -16
Subproblem 2
Set the factor '(6 + -1x)' equal to zero and attempt to solve:

Simplifying
6 + -1x = 0

Solving
6 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -1x = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -1x = 0 + -6
-1x = 0 + -6

Combine like terms: 0 + -6 = -6
-1x = -6

Divide each side by '-1'.
x = 6

Simplifying
x = 6
Solution
x = {-16, 6}